3[x+1]=12

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Solution for 3[x+1]=12 equation: 


Simplifying
3[x + 1] = 12

Reorder the terms:
3[1 + x] = 12
[1 * 3 + x * 3] = 12
[3 + 3x] = 12

Solving
3 + 3x = 12

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 3x = 12 + -3

Combine like terms: 3 + -3 = 0
0 + 3x = 12 + -3
3x = 12 + -3

Combine like terms: 12 + -3 = 9
3x = 9

Divide each side by '3'.
x = 3

Simplifying
x = 3

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